8x^2-18x=35

Solution for 8x^2-18x=35 equation:

8x^2-18x=35

We move all terms to the left:

8x^2-18x-(35)=0

a = 8; b = -18; c = -35;
Δ = b2-4ac
Δ = -182-4·8·(-35)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-38}{2*8}=\frac{-20}{16}
=-1+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+38}{2*8}=\frac{56}{16}
=3+1/2
$